Check whether an element is visible or hidden with Javascript

jQuery

You can say:

$(element).is(':visible')

and

$(element).is(':hidden')

jQuery considers an element to be visible if it consumes space in the document. For most purposes, this is exactly what you want.

Native DOM API

Emulate jQuery's implementation Show archive.org snapshot :

element.offsetWidth > 0 && element.offsetHeight > 0;

jQuery > 3

Query 3 slightly modifies the meaning of :visible (and therefore of :hidden).

Emulate jQuery's implementation:

!(window.getComputedStyle(element).display === "none")

Prototype

Don't use Element#visible(), it just checks if a CSS attribute display: none exists. This is too naive for most cases.

Emulate jQuery's implementation Show archive.org snapshot instead:

element.offsetWidth > 0 && element.offsetHeight > 0;

Or maybe you'd even like to patch Prototype so it behaves like jQuery:

Element.addMethods({
  visible: function() {
    return offsetWidth > 0 && offsetHeight > 0;
  }
});